Search a number
-
+
113221311210 = 232571750321017
BaseRepresentation
bin110100101110010000…
…1000001101011101010
3101211020120212112121200
41221130201001223222
53323334123424320
6124002501345030
711115505160220
oct1513441015352
9354216775550
10113221311210
1144020529987
1219b39708176
13a8a49ba907
1456a0d58b10
152e29d05290
hex1a5c841aea

113221311210 has 192 divisors, whose sum is σ = 356944154112. Its totient is φ = 24307273728.

The previous prime is 113221311179. The next prime is 113221311221. The reversal of 113221311210 is 12113122311.

113221311210 is a `hidden beast` number, since 1 + 1 + 322 + 131 + 1 + 210 = 666.

It is a super-2 number, since 2×1132213112102 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 5376622 + ... + 5397638.

It is an arithmetic number, because the mean of its divisors is an integer number (1859084136).

Almost surely, 2113221311210 is an apocalyptic number.

113221311210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 113221311210, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (178472077056).

113221311210 is an abundant number, since it is smaller than the sum of its proper divisors (243722842902).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113221311210 is a wasteful number, since it uses less digits than its factorization.

113221311210 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21557 (or 21554 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 113221311210 its reverse (12113122311), we get a palindrome (125334433521).

The spelling of 113221311210 in words is "one hundred thirteen billion, two hundred twenty-one million, three hundred eleven thousand, two hundred ten".