Base | Representation |
---|---|
bin | 110100101110010000… |
… | …1010111011000100101 |
3 | 101211020121001001112221 |
4 | 1221130201113120211 |
5 | 3323334134300401 |
6 | 124002503312341 |
7 | 11115506010325 |
oct | 1513441273045 |
9 | 354217031487 |
10 | 113221400101 |
11 | 4402058a747 |
12 | 19b3974b6b1 |
13 | a8a4a1c204 |
14 | 56a0d7d285 |
15 | 2e29d217a1 |
hex | 1a5c857625 |
113221400101 has 4 divisors (see below), whose sum is σ = 113226900192. Its totient is φ = 113215900012.
The previous prime is 113221400077. The next prime is 113221400111. The reversal of 113221400101 is 101004122311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 113221400101 - 215 = 113221367333 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113221400111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2719051 + ... + 2760376.
It is an arithmetic number, because the mean of its divisors is an integer number (28306725048).
Almost surely, 2113221400101 is an apocalyptic number.
It is an amenable number.
113221400101 is a deficient number, since it is larger than the sum of its proper divisors (5500091).
113221400101 is an equidigital number, since it uses as much as digits as its factorization.
113221400101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5500090.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 113221400101 its reverse (101004122311), we get a palindrome (214225522412).
The spelling of 113221400101 in words is "one hundred thirteen billion, two hundred twenty-one million, four hundred thousand, one hundred one".
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