Base | Representation |
---|---|
bin | 110100101110010000… |
… | …1110111111010101011 |
3 | 101211020121021211100021 |
4 | 1221130201313322223 |
5 | 3323334203031410 |
6 | 124002510221311 |
7 | 11115510103660 |
oct | 1513441677253 |
9 | 354217254307 |
10 | 113221533355 |
11 | 44020670877 |
12 | 19b397b4837 |
13 | a8a4a67a68 |
14 | 56a0db5a67 |
15 | 2e29d4aeda |
hex | 1a5c877eab |
113221533355 has 8 divisors (see below), whose sum is σ = 155275245792. Its totient is φ = 77637622848.
The previous prime is 113221533353. The next prime is 113221533361. The reversal of 113221533355 is 553335122311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113221533355 - 21 = 113221533353 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 113221533355.
It is not an unprimeable number, because it can be changed into a prime (113221533353) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1617450442 + ... + 1617450511.
It is an arithmetic number, because the mean of its divisors is an integer number (19409405724).
Almost surely, 2113221533355 is an apocalyptic number.
113221533355 is a deficient number, since it is larger than the sum of its proper divisors (42053712437).
113221533355 is an equidigital number, since it uses as much as digits as its factorization.
113221533355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3234900965.
The product of its digits is 40500, while the sum is 34.
Adding to 113221533355 its reverse (553335122311), we get a palindrome (666556655666).
The spelling of 113221533355 in words is "one hundred thirteen billion, two hundred twenty-one million, five hundred thirty-three thousand, three hundred fifty-five".
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