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1132242433 = 71926173253
BaseRepresentation
bin100001101111100…
…1010011000000001
32220220111212121221
41003133022120001
54304323224213
6304203515041
740025621230
oct10337123001
92826455557
101132242433
11531137553
12277228a81
1315075c54a
14aa532b17
156960438d
hex437ca601

1132242433 has 16 divisors (see below), whose sum is σ = 1363035520. Its totient is φ = 918781056.

The previous prime is 1132242409. The next prime is 1132242451. The reversal of 1132242433 is 3342422311.

It is a cyclic number.

It is not a de Polignac number, because 1132242433 - 217 = 1132111361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1132242398 and 1132242407.

It is not an unprimeable number, because it can be changed into a prime (1132242403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 346435 + ... + 349687.

It is an arithmetic number, because the mean of its divisors is an integer number (85189720).

Almost surely, 21132242433 is an apocalyptic number.

It is an amenable number.

1132242433 is a deficient number, since it is larger than the sum of its proper divisors (230793087).

1132242433 is a wasteful number, since it uses less digits than its factorization.

1132242433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5896.

The product of its digits is 3456, while the sum is 25.

The square root of 1132242433 is about 33648.8102761450. The cubic root of 1132242433 is about 1042.2689715346.

Adding to 1132242433 its reverse (3342422311), we get a palindrome (4474664744).

The spelling of 1132242433 in words is "one billion, one hundred thirty-two million, two hundred forty-two thousand, four hundred thirty-three".

Divisors: 1 7 19 133 2617 3253 18319 22771 49723 61807 348061 432649 8513101 59591707 161748919 1132242433