Base | Representation |
---|---|
bin | 10101000101110011… |
… | …10100100100001111 |
3 | 1002020010020001110020 |
4 | 22202321310210033 |
5 | 141142142013403 |
6 | 5111323113223 |
7 | 550410631011 |
oct | 124271644417 |
9 | 32203201406 |
10 | 11323001103 |
11 | 48905a2357 |
12 | 2240072813 |
13 | 10b5b1986b |
14 | 795b501b1 |
15 | 4640e3453 |
hex | 2a2e7490f |
11323001103 has 8 divisors (see below), whose sum is σ = 15216211968. Its totient is φ = 7489228824.
The previous prime is 11323001071. The next prime is 11323001117. The reversal of 11323001103 is 30110032311.
11323001103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11323001103 - 25 = 11323001071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11323001153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14859201 + ... + 14859962.
It is an arithmetic number, because the mean of its divisors is an integer number (1902026496).
Almost surely, 211323001103 is an apocalyptic number.
11323001103 is a deficient number, since it is larger than the sum of its proper divisors (3893210865).
11323001103 is a wasteful number, since it uses less digits than its factorization.
11323001103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29719293.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11323001103 its reverse (30110032311), we get a palindrome (41433033414).
The spelling of 11323001103 in words is "eleven billion, three hundred twenty-three million, one thousand, one hundred three".
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