Base | Representation |
---|---|
bin | 1010010011000101100101… |
… | …0011010011000001001001 |
3 | 1111002110201120101201002121 |
4 | 2210301121103103001021 |
5 | 2441004032144214423 |
6 | 40025421252531241 |
7 | 2246030201111266 |
oct | 244613123230111 |
9 | 44073646351077 |
10 | 11323032023113 |
11 | 3676086428058 |
12 | 132a590620b21 |
13 | 6419acb448b5 |
14 | 2b207554026d |
15 | 149810da145d |
hex | a4c594d3049 |
11323032023113 has 16 divisors (see below), whose sum is σ = 11395588119552. Its totient is φ = 11250590688000.
The previous prime is 11323032023101. The next prime is 11323032023159. The reversal of 11323032023113 is 31132023032311.
It is a cyclic number.
It is not a de Polignac number, because 11323032023113 - 241 = 9124008767561 is a prime.
It is a super-2 number, since 2×113230320231132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11323032023813) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1594116120 + ... + 1594123222.
It is an arithmetic number, because the mean of its divisors is an integer number (712224257472).
Almost surely, 211323032023113 is an apocalyptic number.
It is an amenable number.
11323032023113 is a deficient number, since it is larger than the sum of its proper divisors (72556096439).
11323032023113 is a wasteful number, since it uses less digits than its factorization.
11323032023113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13776.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 11323032023113 its reverse (31132023032311), we get a palindrome (42455055055424).
The spelling of 11323032023113 in words is "eleven trillion, three hundred twenty-three billion, thirty-two million, twenty-three thousand, one hundred thirteen".
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