Search a number
-
+
113230401053 = 71113669107581
BaseRepresentation
bin110100101110100001…
…1101100111000011101
3101211021012222100112112
41221131003230320131
53323343440313203
6124003424243405
711115645346220
oct1513503547035
9354235870475
10113230401053
1144025678250
1219b40770565
13a8a6851113
1456a22435b7
152e2a9ed6d8
hex1a5d0ece1d

113230401053 has 16 divisors (see below), whose sum is σ = 141182010240. Its totient is φ = 88224206400.

The previous prime is 113230401041. The next prime is 113230401077. The reversal of 113230401053 is 350104032311.

It is not a de Polignac number, because 113230401053 - 26 = 113230400989 is a prime.

It is a super-2 number, since 2×1132304010532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113230401013) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 998723 + ... + 1106303.

It is an arithmetic number, because the mean of its divisors is an integer number (8823875640).

Almost surely, 2113230401053 is an apocalyptic number.

It is an amenable number.

113230401053 is a deficient number, since it is larger than the sum of its proper divisors (27951609187).

113230401053 is a wasteful number, since it uses less digits than its factorization.

113230401053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121268.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 113230401053 its reverse (350104032311), we get a palindrome (463334433364).

The spelling of 113230401053 in words is "one hundred thirteen billion, two hundred thirty million, four hundred one thousand, fifty-three".

Divisors: 1 7 11 77 13669 95683 107581 150359 753067 1052513 1183391 8283737 1470524689 10293672823 16175771579 113230401053