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11323051035 = 354011882469
BaseRepresentation
bin10101000101110100…
…00000110000011011
31002020010022120221120
422202322000300123
5141142200113120
65111324140323
7550411226412
oct124272006033
932203276846
1011323051035
11489062691a
1222400976a3
1310b5b364ca
14795b64479
15464103140
hex2a2e80c1b

11323051035 has 16 divisors (see below), whose sum is σ = 18162070560. Its totient is φ = 6023897600.

The previous prime is 11323051031. The next prime is 11323051063. The reversal of 11323051035 is 53015032311.

It is not a de Polignac number, because 11323051035 - 22 = 11323051031 is a prime.

It is a super-2 number, since 2×113230510352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11323050996 and 11323051014.

It is not an unprimeable number, because it can be changed into a prime (11323051031) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 935220 + ... + 947249.

It is an arithmetic number, because the mean of its divisors is an integer number (1135129410).

Almost surely, 211323051035 is an apocalyptic number.

11323051035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11323051035 is a deficient number, since it is larger than the sum of its proper divisors (6839019525).

11323051035 is a wasteful number, since it uses less digits than its factorization.

11323051035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1882878.

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 11323051035 its reverse (53015032311), we get a palindrome (64338083346).

The spelling of 11323051035 in words is "eleven billion, three hundred twenty-three million, fifty-one thousand, thirty-five".

Divisors: 1 3 5 15 401 1203 2005 6015 1882469 5647407 9412345 28237035 754870069 2264610207 3774350345 11323051035