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113231112013 = 147176975603
BaseRepresentation
bin110100101110100011…
…0011010011101001101
3101211021021022110210101
41221131012122131031
53323344131041023
6124003451411101
711115654400045
oct1513506323515
9354237273711
10113231112013
1144026013418
1219b40a53a91
13a8a6a3c8c6
1456a238a725
152e2aade1ad
hex1a5d19a74d

113231112013 has 4 divisors (see below), whose sum is σ = 113308089088. Its totient is φ = 113154134940.

The previous prime is 113231111989. The next prime is 113231112017. The reversal of 113231112013 is 310211132311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113231112013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113231112017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38486331 + ... + 38489272.

It is an arithmetic number, because the mean of its divisors is an integer number (28327022272).

Almost surely, 2113231112013 is an apocalyptic number.

It is an amenable number.

113231112013 is a deficient number, since it is larger than the sum of its proper divisors (76977075).

113231112013 is an equidigital number, since it uses as much as digits as its factorization.

113231112013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76977074.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 113231112013 its reverse (310211132311), we get a palindrome (423442244324).

The spelling of 113231112013 in words is "one hundred thirteen billion, two hundred thirty-one million, one hundred twelve thousand, thirteen".

Divisors: 1 1471 76975603 113231112013