Base | Representation |
---|---|
bin | 1010010011000101111101… |
… | …0000110011000011100011 |
3 | 1111002110222112120122101221 |
4 | 2210301133100303003203 |
5 | 2441004233244444303 |
6 | 40025435224235511 |
7 | 2246032524136126 |
oct | 244613720630343 |
9 | 44073875518357 |
10 | 11323132031203 |
11 | 3676127924673 |
12 | 132a5ba00bb97 |
13 | 6419c778bc95 |
14 | 2b20849343bd |
15 | 149819a584bd |
hex | a4c5f4330e3 |
11323132031203 has 4 divisors (see below), whose sum is σ = 11325167473048. Its totient is φ = 11321096589360.
The previous prime is 11323132031171. The next prime is 11323132031257. The reversal of 11323132031203 is 30213023132311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11323132031203 - 25 = 11323132031171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11323132031903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1017712578 + ... + 1017723703.
It is an arithmetic number, because the mean of its divisors is an integer number (2831291868262).
Almost surely, 211323132031203 is an apocalyptic number.
11323132031203 is a deficient number, since it is larger than the sum of its proper divisors (2035441845).
11323132031203 is an equidigital number, since it uses as much as digits as its factorization.
11323132031203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2035441844.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 11323132031203 its reverse (30213023132311), we get a palindrome (41536155163514).
The spelling of 11323132031203 in words is "eleven trillion, three hundred twenty-three billion, one hundred thirty-two million, thirty-one thousand, two hundred three".
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