113232132033333 has 4 divisors (see below), whose sum is σ = 150976176044448. Its totient is φ = 75488088022220.

The previous prime is 113232132033247. The next prime is 113232132033353. The reversal of 113232132033333 is 333330231232311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113232132033333 - 2⁴⁵ = 78047759944501 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113232132033294 and 113232132033303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113232132033353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18872022005553 + ... + 18872022005558.

It is an arithmetic number, because the mean of its divisors is an integer number (37744044011112).

Almost surely, 2^{113232132033333} is an apocalyptic number.

It is an amenable number.

113232132033333 is a deficient number, since it is larger than the sum of its proper divisors (37744044011115).

113232132033333 is an equidigital number, since it uses as much as digits as its factorization.

113232132033333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37744044011114.

The product of its (nonzero) digits is 52488, while the sum is 33.

Adding to 113232132033333 its reverse (333330231232311), we get a palindrome (446562363265644).

The spelling of 113232132033333 in words is "one hundred thirteen trillion, two hundred thirty-two billion, one hundred thirty-two million, thirty-three thousand, three hundred thirty-three".