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113232300000000 = 28358587643
BaseRepresentation
bin11001101111101111110011…
…000001001100001100000000
3112211220220100200020202021220
4121233233303001030030000
5104320144222300000000
61040454111150315040
732564522644301106
oct3157576301141400
9484826320222256
10113232300000000
1133096604432145
12108492181b8a80
134b249b5b5a75c
141dd66889d1c76
15d15672dc61a0
hex66fbf304c300

113232300000000 has 648 divisors, whose sum is σ = 377932212748608. Its totient is φ = 30096960000000.

The previous prime is 113232299999983. The next prime is 113232300000013. The reversal of 113232300000000 is 3232311.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 176099999679 + ... + 176100000321.

Almost surely, 2113232300000000 is an apocalyptic number.

113232300000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113232300000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (188966106374304).

113232300000000 is an abundant number, since it is smaller than the sum of its proper divisors (264699912748608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113232300000000 is an frugal number, since it uses more digits than its factorization.

113232300000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1289 (or 1240 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 113232300000000 its reverse (3232311), we get a palindrome (113232303232311).

The spelling of 113232300000000 in words is "one hundred thirteen trillion, two hundred thirty-two billion, three hundred million", and thus it is an aban number.