11323232120131 has 4 divisors (see below), whose sum is σ = 11324065275664. Its totient is φ = 11322398964600.

The previous prime is 11323232120129. The next prime is 11323232120141. The reversal of 11323232120131 is 13102123232311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11323232120131 - 2¹ = 11323232120129 is a prime.

It is a super-2 number, since 2×11323232120131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11323232120096 and 11323232120105.

It is not an unprimeable number, because it can be changed into a prime (11323232120141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 416557380 + ... + 416584561.

It is an arithmetic number, because the mean of its divisors is an integer number (2831016318916).

Almost surely, 2^{11323232120131} is an apocalyptic number.

11323232120131 is a deficient number, since it is larger than the sum of its proper divisors (833155533).

11323232120131 is an equidigital number, since it uses as much as digits as its factorization.

11323232120131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 833155532.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 11323232120131 its reverse (13102123232311), we get a palindrome (24425355352442).

The spelling of 11323232120131 in words is "eleven trillion, three hundred twenty-three billion, two hundred thirty-two million, one hundred twenty thousand, one hundred thirty-one".