Base | Representation |
---|---|
bin | 1010010011000110101100… |
… | …0101100100001110001011 |
3 | 1111002111111100212111200121 |
4 | 2210301223011210032023 |
5 | 2441010140041212301 |
6 | 40025511032244111 |
7 | 2246040453305050 |
oct | 244615305441613 |
9 | 44074440774617 |
10 | 11323330413451 |
11 | 3676219902141 |
12 | 132a654540637 |
13 | 641a298cab24 |
14 | 2b20a3015027 |
15 | 14982c1933a1 |
hex | a4c6b16438b |
11323330413451 has 4 divisors (see below), whose sum is σ = 12940949043952. Its totient is φ = 9705711782952.
The previous prime is 11323330413443. The next prime is 11323330413509. The reversal of 11323330413451 is 15431403332311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11323330413451 - 23 = 11323330413443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11323330413851) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808809315240 + ... + 808809315253.
It is an arithmetic number, because the mean of its divisors is an integer number (3235237260988).
Almost surely, 211323330413451 is an apocalyptic number.
11323330413451 is a deficient number, since it is larger than the sum of its proper divisors (1617618630501).
11323330413451 is an equidigital number, since it uses as much as digits as its factorization.
11323330413451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1617618630500.
The product of its (nonzero) digits is 38880, while the sum is 34.
Adding to 11323330413451 its reverse (15431403332311), we get a palindrome (26754733745762).
The spelling of 11323330413451 in words is "eleven trillion, three hundred twenty-three billion, three hundred thirty million, four hundred thirteen thousand, four hundred fifty-one".
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