Base | Representation |
---|---|
bin | 10101000101111011… |
… | …01011101011110101 |
3 | 1002020012010110221001 |
4 | 22202331223223311 |
5 | 141142421411201 |
6 | 5111400523301 |
7 | 550422345016 |
oct | 124275535365 |
9 | 32205113831 |
10 | 11324013301 |
11 | 4891123887 |
12 | 2240480531 |
13 | 10b60b24b3 |
14 | 795d3500d |
15 | 464243301 |
hex | 2a2f6baf5 |
11324013301 has 4 divisors (see below), whose sum is σ = 11329457004. Its totient is φ = 11318569600.
The previous prime is 11324013299. The next prime is 11324013307. The reversal of 11324013301 is 10331042311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 10331042311 = 19 ⋅543739069.
It can be written as a sum of positive squares in 2 ways, for example, as 7916372676 + 3407640625 = 88974^2 + 58375^2 .
It is a cyclic number.
It is not a de Polignac number, because 11324013301 - 21 = 11324013299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11324013307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2718730 + ... + 2722891.
It is an arithmetic number, because the mean of its divisors is an integer number (2832364251).
Almost surely, 211324013301 is an apocalyptic number.
It is an amenable number.
11324013301 is a deficient number, since it is larger than the sum of its proper divisors (5443703).
11324013301 is an equidigital number, since it uses as much as digits as its factorization.
11324013301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5443702.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 11324013301 its reverse (10331042311), we get a palindrome (21655055612).
The spelling of 11324013301 in words is "eleven billion, three hundred twenty-four million, thirteen thousand, three hundred one".
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