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113241013434 = 2326291167413
BaseRepresentation
bin110100101110110110…
…0001011110010111010
3101211021221221111222200
41221131230023302322
53323404144412214
6124004443531030
711116134506133
oct1513554136272
9354257844880
10113241013434
114403066650a
1219b44229a76
13a8a8ac8633
1456a3806c8a
152e2b8e7d09
hex1a5db0bcba

113241013434 has 12 divisors (see below), whose sum is σ = 245355529146. Its totient is φ = 37747004472.

The previous prime is 113241013433. The next prime is 113241013469. The reversal of 113241013434 is 434310142311.

113241013434 is a `hidden beast` number, since 113 + 2 + 410 + 134 + 3 + 4 = 666.

It can be written as a sum of positive squares in only one way, i.e., 79691596209 + 33549417225 = 282297^2 + 183165^2 .

It is a junction number, because it is equal to n+sod(n) for n = 113241013398 and 113241013407.

It is not an unprimeable number, because it can be changed into a prime (113241013433) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3145583689 + ... + 3145583724.

Almost surely, 2113241013434 is an apocalyptic number.

113241013434 is an abundant number, since it is smaller than the sum of its proper divisors (132114515712).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113241013434 is a wasteful number, since it uses less digits than its factorization.

113241013434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6291167421 (or 6291167418 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 113241013434 its reverse (434310142311), we get a palindrome (547551155745).

The spelling of 113241013434 in words is "one hundred thirteen billion, two hundred forty-one million, thirteen thousand, four hundred thirty-four".

Divisors: 1 2 3 6 9 18 6291167413 12582334826 18873502239 37747004478 56620506717 113241013434