113241013441 has 4 divisors (see below), whose sum is σ = 119201066800. Its totient is φ = 107280960084.

The previous prime is 113241013433. The next prime is 113241013469. The reversal of 113241013441 is 144310142311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113241013441 - 2³ = 113241013433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113241013141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2980026651 + ... + 2980026688.

It is an arithmetic number, because the mean of its divisors is an integer number (29800266700).

Almost surely, 2^113241013441 is an apocalyptic number.

It is an amenable number.

113241013441 is a deficient number, since it is larger than the sum of its proper divisors (5960053359).

113241013441 is an equidigital number, since it uses as much as digits as its factorization.

113241013441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5960053358.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 113241013441 its reverse (144310142311), we get a palindrome (257551155752).

The spelling of 113241013441 in words is "one hundred thirteen billion, two hundred forty-one million, thirteen thousand, four hundred forty-one".