11324131002041 has 48 divisors (see below), whose sum is σ = 13431439803600. Its totient is φ = 9483805140480.

The previous prime is 11324131002029. The next prime is 11324131002073. The reversal of 11324131002041 is 14020013142311.

11324131002041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 8 ways, for example, as 612282775225 + 10711848226816 = 782485^2 + 3272896^2 .

It is a de Polignac number, because none of the positive numbers 2^k-11324131002041 is a prime.

It is a super-2 number, since 2×11324131002041² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11324131001998 and 11324131002016.

It is not an unprimeable number, because it can be changed into a prime (11324131005041) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1878273815 + ... + 1878279843.

It is an arithmetic number, because the mean of its divisors is an integer number (279821662575).

Almost surely, 2^{11324131002041} is an apocalyptic number.

11324131002041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11324131002041 is a deficient number, since it is larger than the sum of its proper divisors (2107308801559).

11324131002041 is a wasteful number, since it uses less digits than its factorization.

11324131002041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8250 (or 8239 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 11324131002041 its reverse (14020013142311), we get a palindrome (25344144144352).

The spelling of 11324131002041 in words is "eleven trillion, three hundred twenty-four billion, one hundred thirty-one million, two thousand, forty-one".