1132414013 has 4 divisors (see below), whose sum is σ = 1199026620. Its totient is φ = 1065801408.

The previous prime is 1132414009. The next prime is 1132414021. The reversal of 1132414013 is 3104142311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3104142311 = 911 ⋅3407401.

It can be written as a sum of positive squares in 2 ways, for example, as 636149284 + 496264729 = 25222^2 + 22277^2 .

It is a cyclic number.

It is not a de Polignac number, because 1132414013 - 2² = 1132414009 is a prime.

It is a super-2 number, since 2×1132414013² = 2564722993677528338, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1132413013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33306278 + ... + 33306311.

It is an arithmetic number, because the mean of its divisors is an integer number (299756655).

Almost surely, 2^1132414013 is an apocalyptic number.

It is an amenable number.

1132414013 is a deficient number, since it is larger than the sum of its proper divisors (66612607).

1132414013 is an equidigital number, since it uses as much as digits as its factorization.

1132414013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66612606.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 1132414013 is about 33651.3597496446. The cubic root of 1132414013 is about 1042.3216173498.

Adding to 1132414013 its reverse (3104142311), we get a palindrome (4236556324).

The spelling of 1132414013 in words is "one billion, one hundred thirty-two million, four hundred fourteen thousand, thirteen".