Base | Representation |
---|---|
bin | 1010010011001010011101… |
… | …0001100110111000100010 |
3 | 1111002121002201222010121002 |
4 | 2210302213101212320202 |
5 | 2441014222042444132 |
6 | 40030155143432002 |
7 | 2246104464341036 |
oct | 244624721467042 |
9 | 44077081863532 |
10 | 11324340203042 |
11 | 3676697901a99 |
12 | 132a896755602 |
13 | 641b5ab84b69 |
14 | 2b215b1901c6 |
15 | 14988ab5a262 |
hex | a4ca7466e22 |
11324340203042 has 4 divisors (see below), whose sum is σ = 16986510304566. Its totient is φ = 5662170101520.
The previous prime is 11324340203039. The next prime is 11324340203081. The reversal of 11324340203042 is 24030204342311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9413722376041 + 1910617827001 = 3068179^2 + 1382251^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11324340202996 and 11324340203014.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2831085050759 + ... + 2831085050762.
Almost surely, 211324340203042 is an apocalyptic number.
11324340203042 is a deficient number, since it is larger than the sum of its proper divisors (5662170101524).
11324340203042 is an equidigital number, since it uses as much as digits as its factorization.
11324340203042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5662170101523.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 11324340203042 its reverse (24030204342311), we get a palindrome (35354544545353).
The spelling of 11324340203042 in words is "eleven trillion, three hundred twenty-four billion, three hundred forty million, two hundred three thousand, forty-two".
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