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11324340203042 = 25662170101521
BaseRepresentation
bin1010010011001010011101…
…0001100110111000100010
31111002121002201222010121002
42210302213101212320202
52441014222042444132
640030155143432002
72246104464341036
oct244624721467042
944077081863532
1011324340203042
113676697901a99
12132a896755602
13641b5ab84b69
142b215b1901c6
1514988ab5a262
hexa4ca7466e22

11324340203042 has 4 divisors (see below), whose sum is σ = 16986510304566. Its totient is φ = 5662170101520.

The previous prime is 11324340203039. The next prime is 11324340203081. The reversal of 11324340203042 is 24030204342311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9413722376041 + 1910617827001 = 3068179^2 + 1382251^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11324340202996 and 11324340203014.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2831085050759 + ... + 2831085050762.

Almost surely, 211324340203042 is an apocalyptic number.

11324340203042 is a deficient number, since it is larger than the sum of its proper divisors (5662170101524).

11324340203042 is an equidigital number, since it uses as much as digits as its factorization.

11324340203042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5662170101523.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 11324340203042 its reverse (24030204342311), we get a palindrome (35354544545353).

The spelling of 11324340203042 in words is "eleven trillion, three hundred twenty-four billion, three hundred forty million, two hundred three thousand, forty-two".

Divisors: 1 2 5662170101521 11324340203042