Base | Representation |
---|---|
bin | 110100101110111011… |
… | …1101000011101000011 |
3 | 101211022011120222112200 |
4 | 1221131313220131003 |
5 | 3323410431430103 |
6 | 124005032124243 |
7 | 11116202145252 |
oct | 1513567503503 |
9 | 354264528480 |
10 | 113244014403 |
11 | 44032326153 |
12 | 19b45236683 |
13 | a8a9609560 |
14 | 56a3d88799 |
15 | 2e2bcdc0a3 |
hex | 1a5dde8743 |
113244014403 has 24 divisors (see below), whose sum is σ = 176248839312. Its totient is φ = 69652433088.
The previous prime is 113244014399. The next prime is 113244014407. The reversal of 113244014403 is 304410442311.
113244014403 is a `hidden beast` number, since 1 + 1 + 3 + 244 + 0 + 14 + 403 = 666.
It is an interprime number because it is at equal distance from previous prime (113244014399) and next prime (113244014407).
It is not a de Polignac number, because 113244014403 - 22 = 113244014399 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113244014407) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 24201 + ... + 476522.
It is an arithmetic number, because the mean of its divisors is an integer number (7343701638).
Almost surely, 2113244014403 is an apocalyptic number.
113244014403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
113244014403 is a deficient number, since it is larger than the sum of its proper divisors (63004824909).
113244014403 is a wasteful number, since it uses less digits than its factorization.
113244014403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 502675 (or 502672 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 113244014403 its reverse (304410442311), we get a palindrome (417654456714).
The spelling of 113244014403 in words is "one hundred thirteen billion, two hundred forty-four million, fourteen thousand, four hundred three".
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