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1132444443312 = 2432721337333667
BaseRepresentation
bin10000011110101010111…
…100101110001010110000
311000021001000000020221100
4100132222330232022300
5122023221234141222
62224123210324400
7144550012642200
oct20365274561260
94007030006840
101132444443312
113a72a3402506
12163585429700
1382a3471a120
143cb4c420400
151e6cdece4ac
hex107aaf2e2b0

1132444443312 has 360 divisors, whose sum is σ = 4077613818096. Its totient is φ = 290593723392.

The previous prime is 1132444443311. The next prime is 1132444443313. The reversal of 1132444443312 is 2133444442311.

1132444443312 is a `hidden beast` number, since 1 + 132 + 44 + 44 + 433 + 12 = 666.

It is an interprime number because it is at equal distance from previous prime (1132444443311) and next prime (1132444443313).

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a nude number because it is divisible by every one of its digits.

It is not an unprimeable number, because it can be changed into a prime (1132444443311) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 3227103 + ... + 3560769.

Almost surely, 21132444443312 is an apocalyptic number.

1132444443312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1132444443312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2038806909048).

1132444443312 is an abundant number, since it is smaller than the sum of its proper divisors (2945169374784).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1132444443312 is a wasteful number, since it uses less digits than its factorization.

1132444443312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 333745 (or 333729 counting only the distinct ones).

The product of its digits is 110592, while the sum is 36.

Adding to 1132444443312 its reverse (2133444442311), we get a palindrome (3265888885623).

It can be divided in two parts, 1132 and 444443312, that added together give a palindrome (444444444).

The spelling of 1132444443312 in words is "one trillion, one hundred thirty-two billion, four hundred forty-four million, four hundred forty-three thousand, three hundred twelve".