Base | Representation |
---|---|
bin | 10101000110000011… |
… | …01001111001001101 |
3 | 1002020021002101020111 |
4 | 22203001221321031 |
5 | 141143203221131 |
6 | 5111435120021 |
7 | 550434242503 |
oct | 124301517115 |
9 | 32207071214 |
10 | 11325054541 |
11 | 4891775109 |
12 | 22408a3011 |
13 | 10b6388408 |
14 | 796126673 |
15 | 46439bab1 |
hex | 2a3069e4d |
11325054541 has 4 divisors (see below), whose sum is σ = 11339782300. Its totient is φ = 11310326784.
The previous prime is 11325054493. The next prime is 11325054551. The reversal of 11325054541 is 14545052311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7335237316 + 3989817225 = 85646^2 + 63165^2 .
It is a cyclic number.
It is not a de Polignac number, because 11325054541 - 211 = 11325052493 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11325054551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7362726 + ... + 7364263.
It is an arithmetic number, because the mean of its divisors is an integer number (2834945575).
Almost surely, 211325054541 is an apocalyptic number.
It is an amenable number.
11325054541 is a deficient number, since it is larger than the sum of its proper divisors (14727759).
11325054541 is an equidigital number, since it uses as much as digits as its factorization.
11325054541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14727758.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 11325054541 in words is "eleven billion, three hundred twenty-five million, fifty-four thousand, five hundred forty-one".
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