11325143220333 has 4 divisors (see below), whose sum is σ = 15100190960448. Its totient is φ = 7550095480220.

The previous prime is 11325143220331. The next prime is 11325143220373. The reversal of 11325143220333 is 33302234152311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11325143220333 - 2¹ = 11325143220331 is a prime.

It is a super-2 number, since 2×11325143220333² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11325143220294 and 11325143220303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11325143220331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1887523870053 + ... + 1887523870058.

It is an arithmetic number, because the mean of its divisors is an integer number (3775047740112).

Almost surely, 2^{11325143220333} is an apocalyptic number.

It is an amenable number.

11325143220333 is a deficient number, since it is larger than the sum of its proper divisors (3775047740115).

11325143220333 is an equidigital number, since it uses as much as digits as its factorization.

11325143220333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3775047740114.

The product of its (nonzero) digits is 38880, while the sum is 33.

Adding to 11325143220333 its reverse (33302234152311), we get a palindrome (44627377372644).

The spelling of 11325143220333 in words is "eleven trillion, three hundred twenty-five billion, one hundred forty-three million, two hundred twenty thousand, three hundred thirty-three".