Base | Representation |
---|---|
bin | 10000011110101111000… |
… | …111010100101110001111 |
3 | 11000021012212111221120001 |
4 | 100132233013110232033 |
5 | 122023342132102120 |
6 | 2224134144305131 |
7 | 144551521662016 |
oct | 20365707245617 |
9 | 4007185457501 |
10 | 1132514331535 |
11 | 3a73298a7574 |
12 | 1635a49121a7 |
13 | 82a46049ac2 |
14 | 3cb57813a7d |
15 | 1e6d51d6e0a |
hex | 107af1d4b8f |
1132514331535 has 16 divisors (see below), whose sum is σ = 1418374192320. Its totient is φ = 866455096320.
The previous prime is 1132514331521. The next prime is 1132514331601. The reversal of 1132514331535 is 5351334152311.
It is not a de Polignac number, because 1132514331535 - 25 = 1132514331503 is a prime.
It is a super-2 number, since 2×11325143315352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1132514331494 and 1132514331503.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 325080 + ... + 1539709.
It is an arithmetic number, because the mean of its divisors is an integer number (88648387020).
Almost surely, 21132514331535 is an apocalyptic number.
1132514331535 is a deficient number, since it is larger than the sum of its proper divisors (285859860785).
1132514331535 is a wasteful number, since it uses less digits than its factorization.
1132514331535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1870098.
The product of its digits is 81000, while the sum is 37.
Adding to 1132514331535 its reverse (5351334152311), we get a palindrome (6483848483846).
The spelling of 1132514331535 in words is "one trillion, one hundred thirty-two billion, five hundred fourteen million, three hundred thirty-one thousand, five hundred thirty-five".
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