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11325200055034 = 25662600027517
BaseRepresentation
bin1010010011001101101010…
…0001101011101011111010
31111002200022122221010210011
42210303122201223223322
52441023002203230114
640030420341212134
72246135005064125
oct244633241535372
944080278833704
1011325200055034
113676a99202578
12132aa9670104a
13641c67062518
142b21dd4593bc
151498db3a61c4
hexa4cda86bafa

11325200055034 has 4 divisors (see below), whose sum is σ = 16987800082554. Its totient is φ = 5662600027516.

The previous prime is 11325200055017. The next prime is 11325200055047. The reversal of 11325200055034 is 43055000252311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 6798028933809 + 4527171121225 = 2607303^2 + 2127715^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11325200054987 and 11325200055005.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2831300013757 + ... + 2831300013760.

Almost surely, 211325200055034 is an apocalyptic number.

11325200055034 is a deficient number, since it is larger than the sum of its proper divisors (5662600027520).

11325200055034 is an equidigital number, since it uses as much as digits as its factorization.

11325200055034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5662600027519.

The product of its (nonzero) digits is 18000, while the sum is 31.

The spelling of 11325200055034 in words is "eleven trillion, three hundred twenty-five billion, two hundred million, fifty-five thousand, thirty-four".

Divisors: 1 2 5662600027517 11325200055034