Base | Representation |
---|---|
bin | 10000011110101111011… |
… | …110100011001100100011 |
3 | 11000021020021222021112121 |
4 | 100132233132203030203 |
5 | 122023400211421011 |
6 | 2224134523005111 |
7 | 144551624511022 |
oct | 20365736431443 |
9 | 4007207867477 |
10 | 1132520420131 |
11 | 3a7332285a71 |
12 | 1635a6969797 |
13 | 82a4739c219 |
14 | 3cb5855a8b9 |
15 | 1e6d59dae71 |
hex | 107af7a3323 |
1132520420131 has 12 divisors (see below), whose sum is σ = 1204216243360. Its totient is φ = 1064875397760.
The previous prime is 1132520420113. The next prime is 1132520420173. The reversal of 1132520420131 is 1310240252311.
It is not a de Polignac number, because 1132520420131 - 221 = 1132518322979 is a prime.
It is a super-2 number, since 2×11325204201312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1132520420096 and 1132520420105.
It is not an unprimeable number, because it can be changed into a prime (1132523420131) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1585560 + ... + 2186101.
Almost surely, 21132520420131 is an apocalyptic number.
1132520420131 is a deficient number, since it is larger than the sum of its proper divisors (71695823229).
1132520420131 is a wasteful number, since it uses less digits than its factorization.
1132520420131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3772734 (or 3772717 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1132520420131 its reverse (1310240252311), we get a palindrome (2442760672442).
The spelling of 1132520420131 in words is "one trillion, one hundred thirty-two billion, five hundred twenty million, four hundred twenty thousand, one hundred thirty-one".
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