Base | Representation |
---|---|
bin | 10000011110110000010… |
… | …000101010000101010101 |
3 | 11000021021012200121221021 |
4 | 100132300100222011111 |
5 | 122023412042234131 |
6 | 2224140112321141 |
7 | 144552144246463 |
oct | 20366020520525 |
9 | 4007235617837 |
10 | 1132533555541 |
11 | 3a7339737883 |
12 | 1635ab2431b1 |
13 | 82a4a01ac5b |
14 | 3cb5a1b9833 |
15 | 1e6d6c32e11 |
hex | 107b042a155 |
1132533555541 has 4 divisors (see below), whose sum is σ = 1192140584800. Its totient is φ = 1072926526284.
The previous prime is 1132533555497. The next prime is 1132533555649. The reversal of 1132533555541 is 1455553352311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1132533555541 - 211 = 1132533553493 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1132533552541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29803514601 + ... + 29803514638.
It is an arithmetic number, because the mean of its divisors is an integer number (298035146200).
Almost surely, 21132533555541 is an apocalyptic number.
It is an amenable number.
1132533555541 is a deficient number, since it is larger than the sum of its proper divisors (59607029259).
1132533555541 is an equidigital number, since it uses as much as digits as its factorization.
1132533555541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59607029258.
The product of its digits is 675000, while the sum is 43.
The spelling of 1132533555541 in words is "one trillion, one hundred thirty-two billion, five hundred thirty-three million, five hundred fifty-five thousand, five hundred forty-one".
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