1132540302435 has 64 divisors (see below), whose sum is σ = 1828749312000. Its totient is φ = 598492863360.

The previous prime is 1132540302419. The next prime is 1132540302457. The reversal of 1132540302435 is 5342030452311.

It is not a de Polignac number, because 1132540302435 - 2⁴ = 1132540302419 is a prime.

It is a super-2 number, since 2×1132540302435² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1132540302396 and 1132540302405.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1090028646 + ... + 1090029684.

It is an arithmetic number, because the mean of its divisors is an integer number (28574208000).

Almost surely, 2^{1132540302435} is an apocalyptic number.

1132540302435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1132540302435 is a deficient number, since it is larger than the sum of its proper divisors (696209009565).

1132540302435 is a wasteful number, since it uses less digits than its factorization.

1132540302435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2456.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 1132540302435 its reverse (5342030452311), we get a palindrome (6474570754746).

The spelling of 1132540302435 in words is "one trillion, one hundred thirty-two billion, five hundred forty million, three hundred two thousand, four hundred thirty-five".