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1132540302441 = 31919869128113
BaseRepresentation
bin10000011110110000101…
…010011001010001101001
311000021021200101101221110
4100132300222121101221
5122023420304134231
62224140513100533
7144552255506652
oct20366052312151
94007250341843
101132540302441
113a7342525929
121635b1557749
1382a4b540bc2
143cb5b054529
151e6d7617046
hex107b0a99469

1132540302441 has 8 divisors (see below), whose sum is σ = 1589530249120. Its totient is φ = 715288612032.

The previous prime is 1132540302419. The next prime is 1132540302457. The reversal of 1132540302441 is 1442030452311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1132540302441 - 29 = 1132540301929 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1132540302399 and 1132540302408.

It is not an unprimeable number, because it can be changed into a prime (1132540342441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9934564000 + ... + 9934564113.

It is an arithmetic number, because the mean of its divisors is an integer number (198691281140).

Almost surely, 21132540302441 is an apocalyptic number.

It is an amenable number.

1132540302441 is a deficient number, since it is larger than the sum of its proper divisors (456989946679).

1132540302441 is a wasteful number, since it uses less digits than its factorization.

1132540302441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19869128135.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 1132540302441 its reverse (1442030452311), we get a palindrome (2574570754752).

The spelling of 1132540302441 in words is "one trillion, one hundred thirty-two billion, five hundred forty million, three hundred two thousand, four hundred forty-one".

Divisors: 1 3 19 57 19869128113 59607384339 377513434147 1132540302441