Base | Representation |
---|---|
bin | 1010010011001110100001… |
… | …0011000100011101111011 |
3 | 1111002200220202200201022020 |
4 | 2210303220103010131323 |
5 | 2441023440330333103 |
6 | 40030455313325523 |
7 | 2246143512013302 |
oct | 244635023043573 |
9 | 44080822621266 |
10 | 11325431105403 |
11 | 36770a7673098 |
12 | 132ab3bb668a3 |
13 | 641ca2b9b90c |
14 | 2b2222001439 |
15 | 1499017e5753 |
hex | a4ce84c477b |
11325431105403 has 32 divisors (see below), whose sum is σ = 16602409574400. Its totient is φ = 6835322124576.
The previous prime is 11325431105377. The next prime is 11325431105413. The reversal of 11325431105403 is 30450113452311.
11325431105403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11325431105403 - 25 = 11325431105371 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11325431105413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2795125 + ... + 5519382.
It is an arithmetic number, because the mean of its divisors is an integer number (518825299200).
Almost surely, 211325431105403 is an apocalyptic number.
11325431105403 is a deficient number, since it is larger than the sum of its proper divisors (5276978468997).
11325431105403 is a wasteful number, since it uses less digits than its factorization.
11325431105403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8315591.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 11325431105403 its reverse (30450113452311), we get a palindrome (41775544557714).
The spelling of 11325431105403 in words is "eleven trillion, three hundred twenty-five billion, four hundred thirty-one million, one hundred five thousand, four hundred three".
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