Base | Representation |
---|---|
bin | 110100101111010000… |
… | …0100011011001100111 |
3 | 101211022220202222111112 |
4 | 1221132200203121213 |
5 | 3323421203212412 |
6 | 124010054055235 |
7 | 11116362264020 |
oct | 1513640433147 |
9 | 354286688445 |
10 | 113254741607 |
11 | 44038392707 |
12 | 19b4894a51b |
13 | a8ab8c4107 |
14 | 56a557bc47 |
15 | 2e2cc0a722 |
hex | 1a5e823667 |
113254741607 has 4 divisors (see below), whose sum is σ = 129433990416. Its totient is φ = 97075492800.
The previous prime is 113254741583. The next prime is 113254741619. The reversal of 113254741607 is 706147452311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113254741607 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113254741007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8089624394 + ... + 8089624407.
It is an arithmetic number, because the mean of its divisors is an integer number (32358497604).
Almost surely, 2113254741607 is an apocalyptic number.
113254741607 is a deficient number, since it is larger than the sum of its proper divisors (16179248809).
113254741607 is an equidigital number, since it uses as much as digits as its factorization.
113254741607 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16179248808.
The product of its (nonzero) digits is 141120, while the sum is 41.
The spelling of 113254741607 in words is "one hundred thirteen billion, two hundred fifty-four million, seven hundred forty-one thousand, six hundred seven".
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