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11330001231 = 331331093881
BaseRepresentation
bin10101000110101001…
…00001100101001111
31002020121101200211020
422203110201211033
5141200440014411
65112133125223
7550524264363
oct124324414517
932217350736
1011330001231
11489454368a
122242489813
1310b73cab53
14796a532a3
15464a27606
hex2a352194f

11330001231 has 16 divisors (see below), whose sum is σ = 15163713120. Its totient is φ = 7524840960.

The previous prime is 11330001211. The next prime is 11330001239. The reversal of 11330001231 is 13210003311.

It is not a de Polignac number, because 11330001231 - 218 = 11329739087 is a prime.

It is a super-3 number, since 3×113300012313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 11330001231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11330001239) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2917411 + ... + 2921291.

It is an arithmetic number, because the mean of its divisors is an integer number (947732070).

Almost surely, 211330001231 is an apocalyptic number.

11330001231 is a deficient number, since it is larger than the sum of its proper divisors (3833711889).

11330001231 is a wasteful number, since it uses less digits than its factorization.

11330001231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7306.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11330001231 its reverse (13210003311), we get a palindrome (24540004542).

The spelling of 11330001231 in words is "eleven billion, three hundred thirty million, one thousand, two hundred thirty-one".

Divisors: 1 3 313 939 3109 3881 9327 11643 973117 1214753 2919351 3644259 12066029 36198087 3776667077 11330001231