11330004443 has 4 divisors (see below), whose sum is σ = 11330476920. Its totient is φ = 11329531968.

The previous prime is 11330004349. The next prime is 11330004451. The reversal of 11330004443 is 34440003311.

11330004443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11330004443 - 2⁸ = 11330004187 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11330007443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 198230 + ... + 248907.

It is an arithmetic number, because the mean of its divisors is an integer number (2832619230).

Almost surely, 2^11330004443 is an apocalyptic number.

11330004443 is a deficient number, since it is larger than the sum of its proper divisors (472477).

11330004443 is an equidigital number, since it uses as much as digits as its factorization.

11330004443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 472476.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 11330004443 its reverse (34440003311), we get a palindrome (45770007754).

The spelling of 11330004443 in words is "eleven billion, three hundred thirty million, four thousand, four hundred forty-three".