Base | Representation |
---|---|
bin | 10101000110101001… |
… | …00010010111100011 |
3 | 1002020121101212020111 |
4 | 22203110202113203 |
5 | 141200440120301 |
6 | 5112133152151 |
7 | 550524306643 |
oct | 124324422743 |
9 | 32217355214 |
10 | 11330004451 |
11 | 4894546047 |
12 | 224248b657 |
13 | 10b73cc45c |
14 | 796a54523 |
15 | 464a28551 |
hex | 2a35225e3 |
11330004451 has 2 divisors, whose sum is σ = 11330004452. Its totient is φ = 11330004450.
The previous prime is 11330004349. The next prime is 11330004523. The reversal of 11330004451 is 15440003311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11330004451 - 215 = 11329971683 is a prime.
It is a super-3 number, since 3×113300044513 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11330004151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665002225 + 5665002226.
It is an arithmetic number, because the mean of its divisors is an integer number (5665002226).
Almost surely, 211330004451 is an apocalyptic number.
11330004451 is a deficient number, since it is larger than the sum of its proper divisors (1).
11330004451 is an equidigital number, since it uses as much as digits as its factorization.
11330004451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 11330004451 its reverse (15440003311), we get a palindrome (26770007762).
The spelling of 11330004451 in words is "eleven billion, three hundred thirty million, four thousand, four hundred fifty-one".
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