Base | Representation |
---|---|
bin | 11001110000101110111100… |
… | …110100001111001001011010 |
3 | 112212011101101110221022122102 |
4 | 121300232330310033021122 |
5 | 104322302111142030242 |
6 | 1040545204012323402 |
7 | 32602443230603501 |
oct | 3160567464171132 |
9 | 485141343838572 |
10 | 113300110111322 |
11 | 33112341480462 |
12 | 1085a3a1773562 |
13 | 4b2b2016a3b94 |
14 | 1dd9a7c83d838 |
15 | d172e1115e32 |
hex | 670bbcd0f25a |
113300110111322 has 4 divisors (see below), whose sum is σ = 169950165166986. Its totient is φ = 56650055055660.
The previous prime is 113300110111277. The next prime is 113300110111351. The reversal of 113300110111322 is 223111011003311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 73421402939641 + 39878707171681 = 8568629^2 + 6314959^2 .
It is a junction number, because it is equal to n+sod(n) for n = 113300110111294 and 113300110111303.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28325027527829 + ... + 28325027527832.
Almost surely, 2113300110111322 is an apocalyptic number.
113300110111322 is a deficient number, since it is larger than the sum of its proper divisors (56650055055664).
113300110111322 is an equidigital number, since it uses as much as digits as its factorization.
113300110111322 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56650055055663.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 113300110111322 its reverse (223111011003311), we get a palindrome (336411121114633).
The spelling of 113300110111322 in words is "one hundred thirteen trillion, three hundred billion, one hundred ten million, one hundred eleven thousand, three hundred twenty-two".
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