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113300120130120 = 233357113109438223
BaseRepresentation
bin11001110000101110111101…
…011010011101001001001000
3112212011101102011210022212000
4121300232331122131021020
5104322302121223130440
61040545205011151000
732602443412012020
oct3160567532351110
9485141364708760
10113300120130120
11331123470a3760
121085a3a4ba5460
134b2b2037a1171
141dd9a7dccaa80
15d172e1e44730
hex670bbd69d248

113300120130120 has 512 divisors, whose sum is σ = 471010166784000. Its totient is φ = 23535255905280.

The previous prime is 113300120130103. The next prime is 113300120130137. The reversal of 113300120130120 is 21031021003311.

113300120130120 is a `hidden beast` number, since 1 + 1 + 330 + 0 + 12 + 0 + 1 + 301 + 20 = 666.

It is an interprime number because it is at equal distance from previous prime (113300120130103) and next prime (113300120130137).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 113300120130093 and 113300120130102.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 258325329 + ... + 258763551.

It is an arithmetic number, because the mean of its divisors is an integer number (919941732000).

Almost surely, 2113300120130120 is an apocalyptic number.

113300120130120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113300120130120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (235505083392000).

113300120130120 is an abundant number, since it is smaller than the sum of its proper divisors (357710046653880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113300120130120 is a wasteful number, since it uses less digits than its factorization.

113300120130120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 441370 (or 441360 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 113300120130120 its reverse (21031021003311), we get a palindrome (134331141133431).

The spelling of 113300120130120 in words is "one hundred thirteen trillion, three hundred billion, one hundred twenty million, one hundred thirty thousand, one hundred twenty".