Base | Representation |
---|---|
bin | 10000011111001100001… |
… | …001011100000101001101 |
3 | 11000022110211001212111020 |
4 | 100133030021130011031 |
5 | 122030341331101404 |
6 | 2224254344344353 |
7 | 144566555133162 |
oct | 20371411340515 |
9 | 4008424055436 |
10 | 1133001425229 |
11 | 3a7559849243 |
12 | 1636bba750b9 |
13 | 82ac2c3351b |
14 | 3cba23aa069 |
15 | 1e712d50ed9 |
hex | 107cc25c14d |
1133001425229 has 4 divisors (see below), whose sum is σ = 1510668566976. Its totient is φ = 755334283484.
The previous prime is 1133001425189. The next prime is 1133001425267. The reversal of 1133001425229 is 9225241003311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1133001425229 - 211 = 1133001423181 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1133001425229.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1133001325229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188833570869 + ... + 188833570874.
It is an arithmetic number, because the mean of its divisors is an integer number (377667141744).
Almost surely, 21133001425229 is an apocalyptic number.
It is an amenable number.
1133001425229 is a deficient number, since it is larger than the sum of its proper divisors (377667141747).
1133001425229 is an equidigital number, since it uses as much as digits as its factorization.
1133001425229 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 377667141746.
The product of its (nonzero) digits is 12960, while the sum is 33.
The spelling of 1133001425229 in words is "one trillion, one hundred thirty-three billion, one million, four hundred twenty-five thousand, two hundred twenty-nine".
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