Base | Representation |
---|---|
bin | 110100110000100111… |
… | …0100001100001100111 |
3 | 101211110002120222022112 |
4 | 1221201032201201213 |
5 | 3324014342100413 |
6 | 124014403351235 |
7 | 11120455026215 |
oct | 1514116414147 |
9 | 354402528275 |
10 | 113300346983 |
11 | 440611016aa |
12 | 19b6008251b |
13 | a8b81a1145 |
14 | 56ab64dcb5 |
15 | 2e31c182a8 |
hex | 1a613a1867 |
113300346983 has 8 divisors (see below), whose sum is σ = 119266617600. Its totient is φ = 107334385848.
The previous prime is 113300346979. The next prime is 113300346997. The reversal of 113300346983 is 389643003311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113300346983 - 22 = 113300346979 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 113300346983.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113300346083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1340660 + ... + 1422662.
It is an arithmetic number, because the mean of its divisors is an integer number (14908327200).
Almost surely, 2113300346983 is an apocalyptic number.
113300346983 is a deficient number, since it is larger than the sum of its proper divisors (5966270617).
113300346983 is an equidigital number, since it uses as much as digits as its factorization.
113300346983 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 154741.
The product of its (nonzero) digits is 139968, while the sum is 41.
The spelling of 113300346983 in words is "one hundred thirteen billion, three hundred million, three hundred forty-six thousand, nine hundred eighty-three".
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