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1133004304101 = 319152313051391
BaseRepresentation
bin10000011111001100010…
…100011010111011100101
311000022111000111010120010
4100133030110122323211
5122030343100212401
62224254530200433
7144566621453325
oct20371424327345
94008430433503
101133004304101
113a756043517a
12163700a23119
1382ac37009b7
143cba2919285
151e71321ded6
hex107cc51aee5

1133004304101 has 16 divisors (see below), whose sum is σ = 1591225712640. Its totient is φ = 715111760880.

The previous prime is 1133004304099. The next prime is 1133004304127. The reversal of 1133004304101 is 1014034003311.

It is not a de Polignac number, because 1133004304101 - 21 = 1133004304099 is a prime.

It is a super-2 number, since 2×11330043041012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133004300101) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6438885 + ... + 6612506.

It is an arithmetic number, because the mean of its divisors is an integer number (99451607040).

Almost surely, 21133004304101 is an apocalyptic number.

It is an amenable number.

1133004304101 is a deficient number, since it is larger than the sum of its proper divisors (458221408539).

1133004304101 is a wasteful number, since it uses less digits than its factorization.

1133004304101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13052936.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1133004304101 its reverse (1014034003311), we get a palindrome (2147038307412).

The spelling of 1133004304101 in words is "one trillion, one hundred thirty-three billion, four million, three hundred four thousand, one hundred one".

Divisors: 1 3 19 57 1523 4569 28937 86811 13051391 39154173 247976429 743929287 19877268493 59631805479 377668101367 1133004304101