Base | Representation |
---|---|
bin | 10000011111001100010… |
… | …100100001101000010011 |
3 | 11000022111000112112012100 |
4 | 100133030110201220103 |
5 | 122030343102102124 |
6 | 2224254530531443 |
7 | 144566621626323 |
oct | 20371424415023 |
9 | 4008430475170 |
10 | 1133004331539 |
11 | 3a7560453853 |
12 | 163700a36b83 |
13 | 82ac3710332 |
14 | 3cba2925283 |
15 | 1e7132271c9 |
hex | 107cc521a13 |
1133004331539 has 12 divisors (see below), whose sum is σ = 1707716673936. Its totient is φ = 722495515632.
The previous prime is 1133004331519. The next prime is 1133004331553. The reversal of 1133004331539 is 9351334003311.
1133004331539 is a `hidden beast` number, since 1 + 1 + 3 + 300 + 4 + 3 + 315 + 39 = 666.
It is not a de Polignac number, because 1133004331539 - 27 = 1133004331411 is a prime.
It is a super-2 number, since 2×11330043315392 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1133004331519) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2736725232 + ... + 2736725645.
It is an arithmetic number, because the mean of its divisors is an integer number (142309722828).
Almost surely, 21133004331539 is an apocalyptic number.
1133004331539 is a deficient number, since it is larger than the sum of its proper divisors (574712342397).
1133004331539 is a wasteful number, since it uses less digits than its factorization.
1133004331539 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5473450906 (or 5473450903 counting only the distinct ones).
The product of its (nonzero) digits is 43740, while the sum is 36.
The spelling of 1133004331539 in words is "one trillion, one hundred thirty-three billion, four million, three hundred thirty-one thousand, five hundred thirty-nine".
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