1133004331553 has 2 divisors, whose sum is σ = 1133004331554. Its totient is φ = 1133004331552.

The previous prime is 1133004331519. The next prime is 1133004331579. The reversal of 1133004331553 is 3551334003311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1056553740544 + 76450591009 = 1027888^2 + 276497^2 .

It is a cyclic number.

It is not a de Polignac number, because 1133004331553 - 2⁸ = 1133004331297 is a prime.

It is a super-3 number, since 3×1133004331553³ (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1133004331583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566502165776 + 566502165777.

It is an arithmetic number, because the mean of its divisors is an integer number (566502165777).

Almost surely, 2^{1133004331553} is an apocalyptic number.

It is an amenable number.

1133004331553 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133004331553 is an equidigital number, since it uses as much as digits as its factorization.

1133004331553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24300, while the sum is 32.

Adding to 1133004331553 its reverse (3551334003311), we get a palindrome (4684338334864).

The spelling of 1133004331553 in words is "one trillion, one hundred thirty-three billion, four million, three hundred thirty-one thousand, five hundred fifty-three".