11330344013 has 4 divisors (see below), whose sum is σ = 11371248060. Its totient is φ = 11289439968.

The previous prime is 11330344007. The next prime is 11330344021. The reversal of 11330344013 is 31044303311.

11330344013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31044303311 = 7 ⋅4434900473.

It can be written as a sum of positive squares in 2 ways, for example, as 7874432644 + 3455911369 = 88738^2 + 58787^2 .

It is a cyclic number.

It is not a de Polignac number, because 11330344013 - 2²⁶ = 11263235149 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11330344013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11330344033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20451608 + ... + 20452161.

It is an arithmetic number, because the mean of its divisors is an integer number (2842812015).

Almost surely, 2^11330344013 is an apocalyptic number.

It is an amenable number.

11330344013 is a deficient number, since it is larger than the sum of its proper divisors (40904047).

11330344013 is an equidigital number, since it uses as much as digits as its factorization.

11330344013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40904046.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 11330344013 its reverse (31044303311), we get a palindrome (42374647324).

The spelling of 11330344013 in words is "eleven billion, three hundred thirty million, three hundred forty-four thousand, thirteen".