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11331002032033 = 58719303240259
BaseRepresentation
bin1010010011100011010001…
…0110011101111110100001
31111010020022000101002222011
42210320310112131332201
52441121343010011113
640033220201512521
72246431536061015
oct244706426357641
944106260332864
1011331002032033
1136794a6280792
1213300357a2741
136426800b6ac8
142b25cdc3c545
15149b2a92563d
hexa4e3459dfa1

11331002032033 has 4 divisors (see below), whose sum is σ = 11350305272880. Its totient is φ = 11311698791188.

The previous prime is 11331002032027. The next prime is 11331002032037. The reversal of 11331002032033 is 33023020013311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331002032033 is a prime.

It is a super-2 number, since 2×113310020320332 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11331002031995 and 11331002032013.

It is not an unprimeable number, because it can be changed into a prime (11331002032037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9651619543 + ... + 9651620716.

It is an arithmetic number, because the mean of its divisors is an integer number (2837576318220).

Almost surely, 211331002032033 is an apocalyptic number.

It is an amenable number.

11331002032033 is a deficient number, since it is larger than the sum of its proper divisors (19303240847).

11331002032033 is an equidigital number, since it uses as much as digits as its factorization.

11331002032033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19303240846.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 11331002032033 its reverse (33023020013311), we get a palindrome (44354022045344).

The spelling of 11331002032033 in words is "eleven trillion, three hundred thirty-one billion, two million, thirty-two thousand, thirty-three".

Divisors: 1 587 19303240259 11331002032033