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113310112133 = 587193032559
BaseRepresentation
bin110100110000111001…
…1110001100110000101
3101211110202222002120202
41221201303301212011
53324024342042013
6124015352540245
711120634030101
oct1514163614605
9354422862522
10113310112133
1144066671379
1219b633b1685
13a8ba20cb3a
1456aca72901
152e329e6858
hex1a61cf1985

113310112133 has 4 divisors (see below), whose sum is σ = 113503145280. Its totient is φ = 113117078988.

The previous prime is 113310112129. The next prime is 113310112159. The reversal of 113310112133 is 331211013311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113310112133 - 22 = 113310112129 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113310117133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96515693 + ... + 96516866.

It is an arithmetic number, because the mean of its divisors is an integer number (28375786320).

Almost surely, 2113310112133 is an apocalyptic number.

It is an amenable number.

113310112133 is a deficient number, since it is larger than the sum of its proper divisors (193033147).

113310112133 is an equidigital number, since it uses as much as digits as its factorization.

113310112133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 193033146.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 113310112133 its reverse (331211013311), we get a palindrome (444521125444).

The spelling of 113310112133 in words is "one hundred thirteen billion, three hundred ten million, one hundred twelve thousand, one hundred thirty-three".

Divisors: 1 587 193032559 113310112133