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11331020120034 = 2310318334984013
BaseRepresentation
bin1010010011100011010101…
…1011011101111111100010
31111010020100021102002001010
42210320311123131333202
52441121412122320114
640033222045321350
72246432145604506
oct244706533357742
944106307362033
1011331020120034
11367950550554a
12133003b866256
13642683a7ab74
142b25d23ca306
15149b2c2e9c59
hexa4e356ddfe2

11331020120034 has 16 divisors (see below), whose sum is σ = 22882060049472. Its totient is φ = 3740336738448.

The previous prime is 11331020120011. The next prime is 11331020120039. The reversal of 11331020120034 is 43002102013311.

It is a super-2 number, since 2×113310201200342 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11331020120039) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9167491389 + ... + 9167492624.

It is an arithmetic number, because the mean of its divisors is an integer number (1430128753092).

Almost surely, 211331020120034 is an apocalyptic number.

11331020120034 is an abundant number, since it is smaller than the sum of its proper divisors (11551039929438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11331020120034 is a wasteful number, since it uses less digits than its factorization.

11331020120034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18334984121.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11331020120034 its reverse (43002102013311), we get a palindrome (54333122133345).

The spelling of 11331020120034 in words is "eleven trillion, three hundred thirty-one billion, twenty million, one hundred twenty thousand, thirty-four".

Divisors: 1 2 3 6 103 206 309 618 18334984013 36669968026 55004952039 110009904078 1888503353339 3777006706678 5665510060017 11331020120034