11331023000121 has 160 divisors (see below), whose sum is σ = 19703773584000. Its totient is φ = 6413108152320.

The previous prime is 11331023000119. The next prime is 11331023000161. The reversal of 11331023000121 is 12100032013311.

11331023000121 is a `hidden beast` number, since 1 + 1 + 3 + 310 + 230 + 0 + 0 + 121 = 666.

11331023000121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11331023000121 - 2¹ = 11331023000119 is a prime.

It is a super-2 number, since 2×11331023000121² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11331023000094 and 11331023000103.

It is not an unprimeable number, because it can be changed into a prime (11331023000161) by changing a digit.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 2737621270 + ... + 2737625408.

It is an arithmetic number, because the mean of its divisors is an integer number (123148584900).

Almost surely, 2^{11331023000121} is an apocalyptic number.

11331023000121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11331023000121 is a deficient number, since it is larger than the sum of its proper divisors (8372750583879).

11331023000121 is a wasteful number, since it uses less digits than its factorization.

11331023000121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5541 (or 5532 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 11331023000121 its reverse (12100032013311), we get a palindrome (23431055013432).

The spelling of 11331023000121 in words is "eleven trillion, three hundred thirty-one billion, twenty-three million, one hundred twenty-one", and thus it is an aban number.