Base | Representation |
---|---|
bin | 1010010011100011011011… |
… | …0100010100000111100011 |
3 | 1111010020101220020100102101 |
4 | 2210320312310110013203 |
5 | 2441121434103113103 |
6 | 40033224240431231 |
7 | 2246432550556453 |
oct | 244706664240743 |
9 | 44106356210371 |
10 | 11331043410403 |
11 | 3679517672992 |
12 | 1330047618517 |
13 | 642688843b52 |
14 | 2b25d552dd63 |
15 | 149b2e39aa1d |
hex | a4e36d141e3 |
11331043410403 has 4 divisors (see below), whose sum is σ = 11331956553880. Its totient is φ = 11330130266928.
The previous prime is 11331043410397. The next prime is 11331043410431. The reversal of 11331043410403 is 30401434013311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11331043410403 - 29 = 11331043409891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11331043410443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 456553125 + ... + 456577942.
It is an arithmetic number, because the mean of its divisors is an integer number (2832989138470).
Almost surely, 211331043410403 is an apocalyptic number.
11331043410403 is a deficient number, since it is larger than the sum of its proper divisors (913143477).
11331043410403 is an equidigital number, since it uses as much as digits as its factorization.
11331043410403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 913143476.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 11331043410403 its reverse (30401434013311), we get a palindrome (41732477423714).
The spelling of 11331043410403 in words is "eleven trillion, three hundred thirty-one billion, forty-three million, four hundred ten thousand, four hundred three".
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