Base | Representation |
---|---|
bin | 1010010011100011011011… |
… | …0100010100000111111111 |
3 | 1111010020101220020100110102 |
4 | 2210320312310110013333 |
5 | 2441121434103113211 |
6 | 40033224240431315 |
7 | 2246432550556523 |
oct | 244706664240777 |
9 | 44106356210412 |
10 | 11331043410431 |
11 | 3679517672a08 |
12 | 133004761853b |
13 | 642688843b74 |
14 | 2b25d552dd83 |
15 | 149b2e39aa3b |
hex | a4e36d141ff |
11331043410431 has 2 divisors, whose sum is σ = 11331043410432. Its totient is φ = 11331043410430.
The previous prime is 11331043410397. The next prime is 11331043410437. The reversal of 11331043410431 is 13401434013311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331043410431 - 242 = 6932996899327 is a prime.
It is a super-2 number, since 2×113310434104312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11331043410394 and 11331043410403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331043410437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665521705215 + 5665521705216.
It is an arithmetic number, because the mean of its divisors is an integer number (5665521705216).
Almost surely, 211331043410431 is an apocalyptic number.
11331043410431 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331043410431 is an equidigital number, since it uses as much as digits as its factorization.
11331043410431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 11331043410431 its reverse (13401434013311), we get a palindrome (24732477423742).
The spelling of 11331043410431 in words is "eleven trillion, three hundred thirty-one billion, forty-three million, four hundred ten thousand, four hundred thirty-one".
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