Base | Representation |
---|---|
bin | 110100110000111011… |
… | …1001101100111001011 |
3 | 101211110211122212210011 |
4 | 1221201313031213023 |
5 | 3324030104411243 |
6 | 124015424132351 |
7 | 11120644502344 |
oct | 1514167154713 |
9 | 354424585704 |
10 | 113311013323 |
11 | 44067127462 |
12 | 19b637670b7 |
13 | a8ba4670a1 |
14 | 56acc290cb |
15 | 2e32b2389d |
hex | 1a61dcd9cb |
113311013323 has 4 divisors (see below), whose sum is σ = 113880415600. Its totient is φ = 112741611048.
The previous prime is 113311013297. The next prime is 113311013341. The reversal of 113311013323 is 323310113311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 323310113311 = 59 ⋅5479832429.
It is a cyclic number.
It is not a de Polignac number, because 113311013323 - 233 = 104721078731 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113311013294 and 113311013303.
It is not an unprimeable number, because it can be changed into a prime (113311013353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 284700840 + ... + 284701237.
It is an arithmetic number, because the mean of its divisors is an integer number (28470103900).
Almost surely, 2113311013323 is an apocalyptic number.
113311013323 is a deficient number, since it is larger than the sum of its proper divisors (569402277).
113311013323 is an equidigital number, since it uses as much as digits as its factorization.
113311013323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 569402276.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 113311013323 its reverse (323310113311), we get a palindrome (436621126634).
The spelling of 113311013323 in words is "one hundred thirteen billion, three hundred eleven million, thirteen thousand, three hundred twenty-three".
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